Sakalova
Sakalova is a hamlet in Brest Oblast, Belarus and has about 170 residents. Sakalova is situated near the hamlet Selishcha, as well as near Alizaraŭ Staŭ.- Hamlet with about 170 residents
- …lies at an elevation of around 140 metres (470 feet)
- …is also known as “Sokolovo”
- Description: village in Žabinka district, Belarus
- Address: Жабінкаўскі раён
Places in the Area
Nearby places include Saki and Sciabrova.
Saki
Hamlet
Saki is a hamlet, which is situated 3 km southwest of Sakalova.
Sciabrova
Neighborhood
Sciabrova is a neighborhood, which is situated 4½ km south of Sakalova.
Sakalova
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Latitude
52.21884° or 52° 13′ 8″ north
Longitude
23.95997° or 23° 57′ 36″ east
Open location code
9G456X95+GX
OpenStreetMap ID
OpenStreetMap feature
place=hamlet
GeoNames ID
Wikidata ID
Satellite Map
Discover this place from above in high-definition satellite imagery.
In Other Languages
From Belarusian to Turkish—“Sakalova” goes by many names.
- Belarusian: “Сакалова”
- Chechen: “Соколово”
- German: “Sakalova”
- Korean: “사칼로바”
- Polish: “Sokołowo”
- Russian: “Соколово”
- Tatar: “Сакалова”
- Turkish: “Sakalova”
Places with the Same Name
Discover other places named “Sakalova”.
Localities in the Area
Explore places such as Selishcha and Alizaraŭ Staŭ.
Notable Places Nearby
Highlights include сажалка Барок and Могілкі.
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