Choctaw Island
Choctaw Island is an island in Lake, Tennessee. Choctaw Island is situated near the hamlet Lake Drive, as well as near Edgewater Beach.Places in the Area
Nearby places include Blue Bank and Tiptonville.
Tiptonville
Village
Tiptonville is a town in and the county seat of Lake County, Tennessee, United States.
Wynnburg
Hamlet
Wynnburg is an unincorporated community and… Wynnburg is situated 5 miles southwest of Choctaw Island.
Choctaw Island
- Type: Island
- Description: island in Lake County, Tennessee, United States
- Categories: locality and landform
- Location: Lake, Tennessee, South, United States, North America
- View on OpenStreetMap
Latitude
36.38395° or 36° 23′ 2″ north
Longitude
-89.41119° or 89° 24′ 40″ west
Elevation
285 feet (87 metres)
Open location code
868G9HMQ+HG
OpenStreetMap ID
OpenStreetMap feature
place=island
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Satellite Map
Discover this place from above in high-definition satellite imagery.
In Other Languages
“Choctaw Island” goes by many names.
- Cebuano: “Choctaw Island”
Places with the Same Name
Discover other places named “Choctaw Island”.
Localities in the Area
Places to explore: Lake Drive and Edgewater Beach.
Notable Places Nearby
Highlights: Caney Island and Rat Island.
Tennessee: Must-Visit Destinations
Worth a closer look: Nashville and Memphis.
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