Sand Hill
Sand Hill is the second highest named summit in the U.S. state of Indiana. It is located in northeastern Wayne Township in Noble County, approximately two and a half miles southeast of the town of South Milford.- Peak rising to 1,073 feet (327 metres)
- Description: mountain in Indiana, United States of America
Hamlets in the Area
Discover Wayne Center and South Milford.
Wayne Center
Wayne Center is an unincorporated community…
South Milford
South Milford is an unincorporated community in Milford Township, LaGrange County, Indiana.
Sand Hill
This page is based on…
We’d love your help improving our open data sources. Thank you for contributing.
Latitude
41.51422° or 41° 30′ 51″ north
Longitude
-85.22497° or 85° 13′ 30″ west
Open location code
86HPGQ7G+M2
OpenStreetMap ID
OpenStreetMap feature
natural = peak
GeoNames ID
Wikidata ID
Satellite Map
See this place from above in high-definition satellite imagery.
In Other Languages
From Cebuano to Japanese—“Sand Hill” goes by many names.
Sand HillCebuano
Sand Hill (bukid sa Estados Unidos, Indiana, Noble County)Cebuano
Sand HillDutch
サンド・ヒルJapanese
サンド丘Japanese
Places with the Same Name
Discover other places named “Sand Hill”.
Localities in the Area
Explore places such as Ramblewood and Lakeview.
Notable Places Nearby
Discover Schockopee Lake and Camp Lakewood.
Curious Peaks to Discover
Uncover intriguing peaks from every corner of the globe.
“Travel is fatal to prejudice, bigotry, and narrow-mindedness.”
Indiana: Highlights
Learn more about Indianapolis and Fort Wayne.
