Summerhill

Summerhill is a town in , , United States. The population was 1,217 at the 2010 census. The town name is that of a location in . Summerhill is in the southeastern corner of the county and is northeast of .
  • Locality with about 1,110 residents
  • …lies at an elevation of around 1,650 feet (500 metres)
  • Description: town in Cayuga County, New York, United States
  • Also known as
    “Summerhill, New York”
    “Summerhill, NY”
    “Town of Summerhill”

Places of Interest

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Latitude
42.6596° or 42° 39′ 34″ north
Longitude
-76.3172° or 76° 19′ 2″ west
Open location code
87J5MM5M+R4
Geo­Names ID
Wiki­data ID

Satellite Map

See this place from above in high-definition satellite imagery.

In Other Languages

From Basque to Uzbek—“Summerhill” goes by many names.
SummerhillBasque
СамерхілBelarusian
СъмърхилBulgarian
SummerhillCatalan
СаммергиллChechen
萨默希尔Chinese
SummerhillHaitian
Summerhill, New YorkHaitian
סאמרהילHebrew
SummerhillHungarian
SummerhillIndonesian
Summerhill, New YorkIndonesian
SummerhillIrish
SummerhillItalian
サマーヒルJapanese
서머힐Korean
سامرهیلMazanderani
سامرهیل (نیویورک)Mazanderani
SummerhillNorwegian
SummerhillNorwegian Bokmål
SummerhillNorwegian Nynorsk
SummerhillPolish
SummerhillSlovenian
СаммергиллTatar
SummerhillTurkish
СаммергіллUkrainian
سمر ہل، نیو یارکUrdu
SummerhillUzbek
Summerhill, New YorkUzbek
СуммерҳиллUzbek

Localities in the Area

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