Hartsgrove Township

Hartsgrove Township is one of the twenty-seven townships of , , United States. The 2020 census found 1,624 people in the township.
  • Type: Locality with 1,620 residents
  • Description: township in Ashtabula County, Ohio
  • Also known as: “Hartsgrove Township, Ashtabula County, Ohio” and “Township of Hartsgrove”

Places in the Area

Nearby places include Footville.

Hamlet
is an unincorporated community in southwestern , , , United States. It lies at the intersection of State Route 166 with Trask Road / Graham Road, 1+1⁄2 miles east of the line and 11+1⁄4 miles southeast of the village of , the county seat of Ashtabula County. is situated 4 miles north of Hartsgrove Township.

Hartsgrove Township

Latitude
41.6067° or 41° 36′ 24″ north
Longitude
-80.9536° or 80° 57′ 13″ west
Population
1,620
Elevation
1,014 feet (309 metres)
Open location code
86HXJ24W+MG
Geo­Names ID
Wiki­data ID
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Satellite Map

Discover Hartsgrove Township from above in high-definition satellite imagery.

In Other Languages

From Basque to Vietnamese—“Hartsgrove Township” goes by many names.
  • Basque: “Hartsgrove udalerria, Ashtabula konderria (Ohio)”
  • Basque: “Hartsgrove udalerria, Ashtabula konderria”
  • Chinese: “哈茨格羅夫鎮區 (俄亥俄州阿什特比拉縣)”
  • Chinese: “哈茨格羅夫鎮區”
  • German: “Hartsgrove Township”
  • Persian: “بخش هارتس گروو، شهرستان اشتابولا”
  • Persian: “بخش هارتس گروو”
  • Portuguese: “Município de Hartsgrove (condado de Ashtabula, Ohio)”
  • Portuguese: “Município de Hartsgrove”
  • Spanish: “Municipio de Hartsgrove”
  • Urdu: “دیستریک هارتس گروو، کانتی اشتابولا، اوهایو”
  • Vietnamese: “Xã Hartsgrove, Quận Ashtabula, Ohio”
  • Vietnamese: “Xã Hartsgrove”

Localities in the Area

Explore places such as Hartsgrove and Stoneville.

Notable Places Nearby

Highlights include Hartsgrove Township Cemetery and Southeast Hartsgrove Cemetery.

Ashtabula County: Must-Visit Destinations

Delve into Ashtabula, Conneaut, and Geneva-on-the-Lake.

Curious Places to Discover

Uncover intriguing places from every corner of the globe.