Great Plains
Nebraska
Sheridan

F Sandoz Ranch

F Sandoz Ranch is in , and has an elevation of 3,960 feet.
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Latitude
42.33693° or 42° 20′ 13″ north
Longitude
-102.2188° or 102° 13′ 8″ west
Elevation
3,960 feet (1,207 metres)
Open location code
85JV8QPJ+QF
Geo­Names ID
5695241
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Satellite Map

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