Siberia Ridge
Siberia Ridge is a ridge in Sweetwater County, Wyoming and has an elevation of 6,985 feet.- Type: Ridge with an elevation of 6,985 feet
- Category: landform
- Location: Sweetwater County, Wyoming, Rocky Mountains, United States, North America
- View on OpenStreetMap
Latitude
41.86579° or 41° 51′ 57″ northLongitude
-108.03286° or 108° 1′ 58″ westElevation
6,985 feet (2,129 metres)Open location code
85HHVX88+8VGeoNames ID
5838338
This page is based on GeoNames, Wikidata, and Wikimedia Commons.
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Satellite Map
Discover Siberia Ridge from above in high-definition satellite imagery.
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