Schokalsky Bay
Schokalsky Bay is the easternmost bay of Alexander Island, Antarctica, 9 nautical miles wide at its entrance and indenting 6 nautical miles lying between Mount Calais and Cape Brown along the east coast of Alexander Island whilst adjacent to the George VI Ice Shelf in George VI Sound.- Cove
- …is also known as “Schokalsky, bahia”
- Description: bay
- Categories
- Location: Antarctica
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Latitude
-69.28113° or 69° 16′ 52″ south
Longitude
-70.00854° or 70° 0′ 31″ west
Open location code
372FPX9R+GH
GeoNames ID
Wikidata ID
Satellite Map
See this place from above in high-definition satellite imagery.
In Other Languages
From Chinese to Swedish—“Schokalsky Bay” goes by many names.
紹卡利斯基灣Chinese
מפרץ שוקאלסקיHebrew
Schokalsky BayNorwegian Nynorsk
Zatoka SzokalskiegoPolish
Schokalsky, bahíaSwedish
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