Schokalsky Bay
Schokalsky Bay is the easternmost bay of Alexander Island, Antarctica, 9 nautical miles wide at its entrance and indenting 6 nautical miles lying between Mount Calais and Cape Brown along the east coast of Alexander Island whilst adjacent to the George VI Ice Shelf in George VI Sound.
Photo: NASA, Public domain.- Type: Cove
- Description: bay
- Also known as: “Schokalsky, bahia”
Schokalsky Bay
- Categories: bay and body of water
- Location: Antarctica
- View on OpenStreetMap
Latitude
-69.28113° or 69° 16′ 52″ south
Longitude
-70.00854° or 70° 0′ 31″ west
Open location code
372FPX9R+GH
GeoNames ID
Wikidata ID
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Satellite Map
Discover this place from above in high-definition satellite imagery.
In Other Languages
From Chinese to Swedish—“Schokalsky Bay” goes by many names.
- Chinese: “紹卡利斯基灣”
- German: “Schokalskibucht”
- Hebrew: “מפרץ שוקאלסקי”
- Norwegian Nynorsk: “Schokalsky Bay”
- Polish: “Zatoka Szokalskiego”
- Spanish: “Bahía Schokalsky”
- Spanish: “Schokalsky, bahía”
- Swedish: “Schokalsky, bahía”
Notable Places Nearby
Highlights: Hahn, Mount and Chokalskii Bay.
Antarctica: Must-Visit Destinations
Worth a closer look: Livingston Island and Villa Las Estrellas.
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