Boumhallouch

Boumhallouch is a hill in Midelt Province, Drâa-Tafilalet and has an elevation of 1,926 metres. Boumhallouch is situated nearby to the locality Ocar Tattiwiyn, as well as near Mmourazziz.

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Latitude

32.58766° or 32° 35′ 16″ north

Longitude

-4.75183° or 4° 45′ 7″ west

Elevation

1,926 metres (6,319 feet)

Open location code

8C4QH6QX+37

GeoNames ID

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About Mapcarta. Text is available under the CC BY-SA 4.0 license, except for photos, directions, and the map. Photo: Chrizirox, CC BY-SA 3.0.