Serpent’s Tooth
Serpent’s Tooth is a peak in Gilgit-Baltistan, Pakistan and has an elevation of 5,361 metres. Serpent’s Tooth is situated nearby to the village Bulchi, as well as near Farfoo.- Type: Peak with an elevation of 5,361 metres
- Category: landform
- Location: Gilgit-Baltistan, Pakistan, South Asia, Asia
- View on OpenStreetMap
Latitude
36.0764° or 36° 4′ 35″ northLongitude
74.5139° or 74° 30′ 50″ eastElevation
5,361 metres (17,589 feet)Open location code
8J8P3GG7+HHOpenStreetMap ID
node 11949020274OpenStreetMap feature
natural=peak
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Satellite Map
Discover Serpent’s Tooth from above in high-definition satellite imagery.
Places with the Same Name
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Localities in the Area
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