San Cristóbal Texcalucan

San Cristóbal Texcalucan is a locality in , and has an elevation of 2,558 metres. San Cristóbal Texcalucan is situated nearby to the locality , as well as near .
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Places in the Area

Nearby places include Santa Fe and Bosques de las Lomas.

is in the western area of . It is the newest and most modern district of the city, as almost all of it has been developed only in the past twenty years; this puts this district in stark contrast with Mexico City's other districts, especially the .

Neighborhood
is a colonia, or officially recognised neighbourhood, located in western . It falls partly in borough and partly in borough. is situated 7 km east of San Cristóbal Texcalucan.

Village
Santa Fé de México was a Pueblo Hospital founded by Vasco de Quiroga in 1532. Its ruins are located in the town of Santa Fé in the delegación of Álvaro Obregón in western . is situated 9 km east of San Cristóbal Texcalucan.

San Cristóbal Texcalucan

Latitude
19.40969° or 19° 24′ 35″ north
Longitude
-99.3173° or 99° 19′ 2″ west
Elevation
2,558 metres (8,392 feet)
Open location code
76F2CM5M+V3
Geo­Names ID
3519554
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Satellite Map

Discover San Cristóbal Texcalucan from above in high-definition satellite imagery.

In Other Languages

“San Cristóbal Texcalucan” goes by many names.

Localities in the Area

Explore places such as Barrio del Río and El Escobal.

Notable Places Nearby

Highlights include Estación San Bartolito and Las Viboras.

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About Mapcarta. Text is available under the CC BY-SA 4.0 license, except for photos, directions, and the map. Photo: Wikimedia, CC0.